Many Prime

The challenge is straightforward - just factor out the modulus used N. There are two approaches, one using FactorDB and one using the intended way of using Sage. Credits to pdro solution on Cryptohack: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 n = 580642391898843192929563856870897799650883152718761762932292482252152591279871421569162037190419036435041797739880389529593674485555792234900969402019055601781662044515999210032698275981631376651117318677368742867687180140048715627160641771118040372573575479330830092989800730105573700557717146251860588802509310534792310748898504394966263819959963273509119791037525504422606634640173277598774814099540555569257179715908642917355365791447508751401889724095964924513196281345665480688029639999472649549163147599540142367575413885729653166517595719991872223011969856259344396899748662101941230745601719730556631637 ''' Key observation: the number is 2033 bits and it has 30+ factors. The smallest factor will be ~2033/30 = 68 bits in the worst case (i....